Question

1. You are in the lab. You perform the following chemical reaction by mixing a piece of magne

applying heat and oxygen. Balance the following chemical equation that represents this rea
2
0₂ →
Mg+
MgO
Mg=12
Mg-x2
0 +2
2. What is the mole to mole ratio of Mg to MAO in the chemical equation above?
mol Mg:
mol MgO
3. Calculate the molar mass of the following (1 pt ea.):

Answer 1

1. The balanced chemical equation for the reaction is:

2Mg + O2 → 2MgO

2. The mole to mole ratio of Mg to MgO is 2:2 or 1:1. This means that for every 1 mole of Mg that reacts, 1 mole of MgO is produced.

mol Mg: mol MgO = 1:1

3. Molar mass of the following:

- NaCl (sodium chloride) = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
- H2SO4 (sulfuric acid) = 2(1.01 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.08 g/mol
- Ca(NO3)2 (calcium nitrate) = 1(40.08 g/mol) + 2(14.01 g/mol + 3(16.00 g/mol)) = 164.09 g/mol
- C6H12O6 (glucose) = 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol