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If f(x) = 1/2x^2 -(1/4x + 3), what is the value of f(8)?

2 Answers

2 votes

To find the value of
\sf f(8) \\ for the function
\sf f(x) = (1)/(2)x^2 - \left((1)/(4)x + 3\right) \\, we substitute
\sf x = 8 \\ into the function.


\sf f(8) = (1)/(2)(8)^2 - \left((1)/(4)(8) + 3\right) \\

Simplifying inside the parentheses:


\sf f(8) = (1)/(2)(64) - \left((1)/(4)(8) + 3\right) \\


\sf f(8) = 32 - \left(2 + 3\right) \\


\sf f(8) = 32 - 5 \\

Finally, subtracting:


\sf f(8) = 27 \\

Therefore, the value of
\sf f(8) \\ is 27.

User Nishant Nagwani
by
7.6k points
4 votes

Answer:

f(8) = 27

Explanation:

to evaluate f(8) substitute x = 8 into f(x)

f(8) =
(1)/(2) × 8² - (
(1)/(4) (8) + 3)

=
(1)/(2) × 64 - (2+ 3)

= 32 - 5

= 27

User Zappa
by
7.4k points

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