Question

40 points if someone gets it right.

You spin a spinner that is equally divided into 7 parts. 1 part is pink, 2 parts are green, 1 part is black, and 3 parts are purple.

After that, you radomly pull a flying disc from the bag of flying discs. The bag has 4 red flying discs, 3 pink flying discs, 1 white flying discs, and 4 black flying discs.

What is the probability of the spinner stopping at a pink section and then drawing a red flying disc.

Answer 1

First, we have to acknowledge that the spinner's outcome is independent from the disc pulled from the bag.

For the spinner, there are 7 outcomes (7 spots we could land upon) and only 1 of which is pink. We have a 1/7 chance of landing on pink.

For the bag of discs, there are 12 possible outcomes (12 discs we could pick) and 4 are red. We have a 4/12 chance of pulling a red disc. 4/12 = 1/3

For the overall probability, since the two events are independent, we multiply the individual probabilities to find the overall probability:

1/7 · 1/3 = 1/21

We have a 1/21 (about 4.762%) chance of having the spinner land on pink and then pulling a red disc from the bag.