Question

twice a number minus a second number is -1. Twice the second number added to three times the first number is 9. find the two numbers

Answer 1

Let x be the first number and y be the second number.

From the problem, we know that:

2x - y = -1 (equation 1)
3x + 2y = 9 (equation 2)

We can solve for x in equation 1:

2x - y = -1
2x = y - 1
x = (y - 1)/2

Now we can substitute this expression for x into equation 2:

3x + 2y = 9
3((y - 1)/2) + 2y = 9
(3y - 3)/2 + 2y = 9
3y - 3 + 4y = 18
7y = 21
y = 3

We can now substitute y = 3 into equation 1 to find x:

2x - y = -1
2x - 3 = -1
2x = 2
x = 1

Therefore, the two numbers are x = 1 and y = 3.

Answer 2

1 and 3

Explanation:

let x be the first number and y the second number, then

2x - y = - 1 ( subtract 2x from both sides )

- y = - 1 - 2x ( multiply through by - 1 )

y = 1 + 2x → (1)

2y + 3x = 9 → (2)

substitute y = 1 + 2x into (2)

2(1 + 2x) + 3x = 9

2 + 4x + 3x = 9

2 + 7x = 9 ( subtract 2 from both sides )

7x = 7 ( divide both sides by 7 )

x = 1

substitute x = 1 into (1)

y = 1 + 2x = 1 + 2(1) = 1 + 2 = 3

first number is 1 and second number is 3