Question

Find the slope , X-int , Y-int , of the line : a, (x+2) (x+3)=(x-2)(x-3) +Y

b, 6(x+y) = 3 (x-Y)​

Answer 1

Explanation:

From this equation, we can see that the slope (m) is 10 and the y-intercept (b) is 0.

b) To find the slope, x-intercept, and y-intercept of the line given by the equation 6(x+y) = 3(x-Y), let's simplify the equation:

6(x+y) = 3(x-Y)

6x + 6y = 3x - 3y

Now, let's rearrange the equation to get it in the form y = mx + b:

6y + 3y = -6x + 3x

9y = -3x

Dividing both sides of the equation by 9, we get:

y = -1/3x

From this equation, we can see that the slope (m) is -1/3. However, there are no x-intercepts or y-intercepts since the equation represents a line that passes through the origin (0,0) and does not intersect the x-axis or y-axis at any other point.