Question

Determine the exact values of x for x^2 - 8x - 5 = 0 using COMPLETING THE SQUARE

Answer 1

x = 4 - √21.
x = 4 + √21

Explanation:

To determine the exact values of x for x^2 - 8x - 5 = 0 using completing the square, follow these steps:

Move the constant term to the right side of the equation: x^2 - 8x = 5

Take half of the coefficient of x (-8/2 = -4) and square it (-4^2 = 16): x^2 - 8x + 16 = 5 + 16

Simplify the right side: x^2 - 8x + 16 = 21

Factor the left side as a perfect square: (x - 4)^2 = 21

Take the square root of both sides: x - 4 = ±√21

Add 4 to both sides: x = 4 ±√21

Therefore, the exact values of x for x^2 - 8x - 5 = 0 are x = 4 + √21 and x = 4 - √21.

Brinliest Pls

Answer 2

• The exact values of x are:

x = 4 + √ 21

x = 4 - √ 21

Explanation:

Determine the exact values of x for x^2 - 8x - 5 = 0 using COMPLETING THE SQUARE:

• Rewrite the equation:

x^2 - 8x - 5 = 0

• Move the constant term to the right side:

x^2 - 8x = 5

• Calculate the square of half of the coefficient of the linear term:

( -8/2 )^2 = 16

• Add the square to both sides:

x^2 - 8x + 16 = 5 + 16

• Simplify:

x^2 - 8x + 16 = 21

• Take the square root of both sides:

x - 4 = ±√21

• Solve for x:

x - 4 = ±√21

• Draw a conclusion:

The exact values of x are: x = 4 +√21 and x = 4 - √21

I hope this helps!