Answer: 33,3% Al by mass
Step-by-step explanation:
Question's formatting is a little unclear. I'm assuming it's asking for the "percent" composition by mass of Aluminum in Al2SiO5.
Suppose we have 100g of Al2SiO5 to make the calculations easier.
100 g Al2SiO5
x 1 mol Al2SiO5 / (162,05 g Al2SiO5)
x 1 mol Al2 / (1 mol Al2SiO5)
x 2 mol Al / (1 mol Al2)
x 26,98 g Al / (1 mol Al)
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33.30 g Al
Therefore, 33.30 g / 100 g = 33,3% Al by mass