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find the equation of the line passing through the points (6,-4) and perpendicular to y=-6x+18. If possible, put the final equation in slope intercept form.

User Miligraf
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Answer:

y = -6x + 18 is y = 1/6x - 5 in slope-intercept form.

Explanation:

o find the equation of a line perpendicular to another line, we need to determine the negative reciprocal of the slope of the given line.

The given line has a slope of -6. The negative reciprocal of -6 is 1/6. Therefore, the slope of the line we are looking for is 1/6.

Now, we have the slope (m) and one point (6, -4) through which the line passes. We can use the point-slope form of the equation to find the equation of the line:

y - y1 = m(x - x1)

where (x1, y1) is the given point, and m is the slope.

Substituting the values, we have:

y - (-4) = 1/6(x - 6)

Simplifying:

y + 4 = 1/6x - 1

y = 1/6x - 1 - 4

y = 1/6x - 5

Therefore, the equation of the line passing through (6, -4) and perpendicular to y = -6x + 18 is y = 1/6x - 5 in slope-intercept form.

User ZNackasha
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