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A virtual image is formed 15.0 cm from a concave mirror having a radius of curvature of 35.5 cm.

(a) Find the position of the object.


(b) What is the magnification of the mirror?

User RichardAE
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1 Answer

3 votes

Answer: approximately 8.13 cm from the concave mirror and the magnification of the mirror is approximately 1.85.

Step-by-step explanation:

To solve this problem, we can use the mirror equation and the magnification formula for concave mirrors.

(a) The mirror equation is given by:

1/f = 1/do + 1/di

where f is the focal length of the mirror, do is the object distance, and di is the image distance.

Given:

f = radius of curvature/2 = 35.5 cm / 2 = 17.75 cm

di = -15.0 cm (negative sign indicates a virtual image)

Substituting these values into the mirror equation, we can solve for do:

1/17.75 = 1/do - 1/15.0

Simplifying the equation:

1/do = 1/17.75 + 1/15.0

1/do = (15.0 + 17.75)/(17.75 * 15.0)

1/do = 32.75/(266.25)

1/do ≈ 0.123

Taking the reciprocal of both sides:

do ≈ 1/0.123

do ≈ 8.13 cm

Therefore, the position of the object is approximately 8.13 cm from the concave mirror.

(b) The magnification (m) of the mirror can be determined using the formula:

m = -di/do

Substituting the given values:

m = -(-15.0 cm) / 8.13 cm

m ≈ 1.85

Therefore, the magnification of the mirror is approximately 1.85.

User Satyaki Sanyal
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