Question

21 points if someone gets it right.

Finn was setting up a room with tables for an event. The room had 12 cherry tables and 9 walnut tables. Each table can seat 11 people.

What is the probability that the first person to enter the room will be randomly seated at a cherry table. Give your answer as a reduced fraction

Answer 1

There are a total of 21 tables, 12 of which are cherry and 9 of which are walnut. Since each table has the same number of seats, the probability that the first person to enter the room will be randomly seated at a cherry table is equal to the fraction of cherry tables out of the total number of tables.

So the probability is:

P(seated at cherry table) = number of cherry tables / total number of tables

P(seated at cherry table) = 12 / 21

We can simplify this fraction by dividing both the numerator and denominator by their greatest common factor, which is 3:

P(seated at cherry table) = (12/3) / (21/3)

P(seated at cherry table) = 4/7

Therefore, the probability that the first person to enter the room will be randomly seated at a cherry table is 4/7.