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What is sin b in a 15,8,17 triangle

User Sallar
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1 Answer

1 vote

Answer:


Sin B=(8)/(17)

Explanation:

The sin of an angle is equal to opposite/hypotenuse

Use Pythagorean’s Theorem to solve for the opposite side


15^2 + b^2 = 17^2\\225 + b^2 = 289\\b^2 = 64\\b = 8


SinB = (Oposite)/(Hypotenuse)

The opposite side is equal to 8


So~SinB = (8)/(17)

User Genesis
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