Answer:
q^2 = 0.0025
q ≈ 0.05
p ≈ 0.95
p^2 ≈ 0.9025
2pq ≈ 0.095
Step-by-step explanation:
To solve for the frequencies, we can use the Hardy-Weinberg equation, which relates allele frequencies to genotype frequencies in a population. In this case, we have the following information:
The population reached 8,000 frogs by 2050.
The frequency of the homozygous recessive genotype (ss) is 20.
Let's calculate the frequencies:
q^2 represents the frequency of the homozygous recessive genotype (ss). In this case, q^2 = 20/8000 = 0.0025.
q represents the frequency of the recessive allele. To find q, we can take the square root of q^2: q = √(0.0025) ≈ 0.05.
p represents the frequency of the dominant allele. Since p + q = 1, p ≈ 1 - q ≈ 1 - 0.05 = 0.95.
p^2 represents the frequency of the homozygous dominant genotype (SS). p^2 ≈ (0.95)^2 ≈ 0.9025.
2pq represents the frequency of the heterozygous genotype (Ss). 2pq ≈ 2(0.95)(0.05) ≈ 0.095.