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A 61.0 kg sled is pulled from rest by a snowmobile and accelerates at 2.4 [forward] for 5.5 s. The force of friction acting on the sled is 111.0 N [backwards]. The total mass of the snowmobile and the driver is 461.0 kg and the force of friction acting on the snowmobile is 546.0 N [backwards]. Determine the power developed by the snowmobile engine.

User Marcelo Tataje
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1 Answer

16 votes
16 votes

Answer:

1922.8 watts

Step-by-step explanation:

To find the power developed by the snowmobile engine, we first need to determine the force that the snowmobile is applying to the sled. We can use Newton's second law to do this. The equation for Newton's second law is:F = maWhere F is the force applied, m is the mass, and a is the acceleration. We can rearrange this equation to solve for the force applied by the snowmobile:F = ma = (61.0 kg)(2.4 m/s^2) = 146.4 N [forward]Now that we know the force applied by the snowmobile, we can use the equation for power to determine the power developed by the snowmobile engine:P = FvWhere P is the power, F is the force applied, and v is the velocity. We don't know the velocity of the sled, but we do know that the sled accelerates at a rate of 2.4 m/s^2 for 5.5 seconds. We can use this information to find the velocity of the sled at the end of the 5.5 seconds:v = atWhere v is the velocity, a is the acceleration, and t is the time. Substituting the values from the problem gives us:v = (2.4 m/s^2)(5.5 s) = 13.2 m/sNow that we know the velocity of the sled, we can substitute this value into the equation for power to find the power developed by the snowmobile engine:P = (146.4 N)(13.2 m/s) = 1922.8 wattsTherefore, the power developed by the snowmobile engine is 1922.8 watts.

User AspOnMyNet
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