148k views
1 vote
. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.​

User Simpadjo
by
8.4k points

1 Answer

2 votes

Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :

Step 1: Calculate the velocity using the equation:


v = u + at

where:

-
v is the final velocity

-
u is the initial velocity (0 m/s, as the car starts from rest)

-
a is the acceleration (3 m/s²)

-
t is the time (50 seconds)

Substituting the values into the equation:


v = 0 + (3 \, \text{m/s²}) * (50 \, \text{s})

Step 2: Calculate the distance traveled using the equation:


s = ut + (1)/(2)at^2

where:

-
s is the distance traveled

-
u is the initial velocity (0 m/s)

-
a is the acceleration (3 m/s²)

-
t is the time (50 seconds)

Substituting the values into the equation:


s = 0 * (50 \, \text{s}) + (1)/(2) * (3 \, \text{m/s²}) * (50 \, \text{s})^2

Now, let's simplify these equations:


v = 3 * 50


s = (1)/(2) * 3 * 50^2

Calculating the results:


v = 150 m/s


s = 3750 meters

Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.

User Kojiro
by
8.4k points

Related questions

1 answer
3 votes
49.5k views