Question

. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.​

Answer 1

Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :

Step 1: Calculate the velocity using the equation:

`v = u + at`

where:

-
`v` is the final velocity

-
`u` is the initial velocity (0 m/s, as the car starts from rest)

-
`a` is the acceleration (3 m/s²)

-
`t` is the time (50 seconds)

Substituting the values into the equation:

`v = 0 + (3 \, \text{m/s²}) * (50 \, \text{s})`

Step 2: Calculate the distance traveled using the equation:

`s = ut + (1)/(2)at^2`

where:

-
`s` is the distance traveled

-
`u` is the initial velocity (0 m/s)

-
`a` is the acceleration (3 m/s²)

-
`t` is the time (50 seconds)

Substituting the values into the equation:

`s = 0 * (50 \, \text{s}) + (1)/(2) * (3 \, \text{m/s²}) * (50 \, \text{s})^2`

Now, let's simplify these equations:

`v = 3 * 50`

`s = (1)/(2) * 3 * 50^2`

Calculating the results:

`v = 150` m/s

`s = 3750` meters

Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.