Answer:
Solve the equation for x,y,z and t if 2[
x
y
z
t
]+3[
1
0
−1
2
]=3[
3
4
5
6
]
Explanation:
Solution
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2[
x
y
z
t
]+3[
1
0
−1
2
]=3[
3
4
5
6
]
⇒[
2x
2y
2z
2t
]+[
3
0
−3
6
]=[
9
12
15
18
]
⇒[
2x+3
2y
2z−3
2t+6
]=[
9
12
15
18
]
Comparing the corresponding elements of these two matrices, we get:
2x+3=9⇒2x=6⇒x=3
2y=12⇒y=6
2z−3=15⇒2z=18⇒z=9
2t+6=18⇒2t=12t=6
∴x=3,y=6,z=9 and t=6