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What is the electric force between 2 forces .0042c and -0.0050c and are .0030m apart

User Jwanga
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1 Answer

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To calculate the electric force between two charges, we can use Coulomb's law:

F = k * |q1 * q2| / r^2

where F is the electric force, k is the electrostatic constant (k ≈ 8.99 × 10^9 N m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

In this case, q1 = 0.0042 C, q2 = -0.0050 C, and r = 0.0030 m.

Substituting these values into the equation:

F = (8.99 × 10^9 N m^2/C^2) * |0.0042 C * (-0.0050 C)| / (0.0030 m)^2

F = (8.99 × 10^9 N m^2/C^2) * 0.000021 C^2 / 0.000009 m^2

F ≈ 1977.78 N

Therefore, the electric force between the two charges is approximately 1977.78 Newtons.

User Chris Rutkowski
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