Question

What is the pvalue of a simple random sample of 100 with a hypothesis of 9, sample average of 8.3, and a standard deviation of 4.3

Answer 1

To calculate the p-value, we need to use a statistical test, such as a t-test or z-test, depending on the sample size and whether or not the population standard deviation is known.

Assuming the population standard deviation is unknown and the sample size is greater than 30, we can use a t-test.

The formula for the t-statistic is:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values, we get:

t = (8.3 - 9) / (4.3 / sqrt(100)) = -1.74

Using a t-distribution table with 99 degrees of freedom (sample size - 1), we find that the p-value for a two-tailed test at a significance level of 0.05 is approximately 0.086.

Therefore, we can conclude that there is not enough evidence to reject the null hypothesis at a significance level of 0.05.

Hope it helps