Question

To Make Things Easier, The Following are the Molar Masses (grams/mol) for the Elements that will be used for this Exam:

H-1.01, B-10.81, C12.01, N-14.01, 0-16.00, Na-23.00, C-32.06, C-35.45, Mn 54.94, 1-126.90, Ba 137.33

Solve for Molar Mass
a) (NH₂)₂SO4 =
b) (NH4)₂CO3-
c) NaBO3-
d) BaSO4=
Blank 1:
Blank 2:
Blank 3:
Blank 4:
8/1 mol
8/1 mol
8/1 mol
8/1 mol

Answer 1

a) 128.12

b) 96.11

c) 81.81

d) 233.39

Step-by-step explanation:

notice how many times each atom appears in the molecule, then multiply it by its molar mass

a) (NH₂)₂SO4 = ((14.01+(1.01×2))×2)+32.06+(16.00×4)= 128.12

b) (NH4)₂CO3= ((14.01+(1.01×4))×2)+12.01+(16.00×3)= 96.11

c) NaBO3= 23.00+10.81+(16.00×3)= 81.81

d) BaSO4= 137.33+32.06+(16.00×4)= 233.39

hope my explanation was clear!