Question

For the titration of sulfuric acid (H2SO4) with sodium hydroxide (NaOH), how many moles of sodium hydroxide would be required to react with 1.65 L of 0.500 M sulfuric acid to reach the endpoint? a. 1.65 mol

b. 3.30 mol
c. 0.413 mol
d. 0.825 mol
e. none of these

Answer 1

To titrate 1.65 L of 0.500 M sulfuric acid with sodium hydroxide, 1.65 moles of NaOH are required, since sulfuric acid is diprotic and reacts with NaOH in a 1:2 ratio.

Step-by-step explanation:

To determine the number of moles of sodium hydroxide (NaOH) required to react with 1.65 L of 0.500 M sulfuric acid (H2SO4) to reach the titration endpoint, we must first understand the stoichiometry of the reaction. Sulfuric acid is a diprotic acid, meaning it can donate two protons (H+) per molecule. The balanced chemical equation for the reaction is:

H2SO4 (aq) + 2NaOH(aq) → Na2SO4 (aq) + 2H2O(l)

From the equation, we see that each mole of sulfuric acid reacts with two moles of sodium hydroxide. To find out how many moles of sulfuric acid we have, we multiply the volume of the solution by its molarity:

Moles of H2SO4 = 1.65 L × 0.500 M = 0.825 mol

Since it takes 2 moles of NaOH to neutralize 1 mole of H2SO4, we multiply the moles of sulfuric acid by 2:

Moles of NaOH required = 0.825 mol H2SO4 × 2 = 1.65 mol

Therefore, the correct answer is a. 1.65 mol of sodium hydroxide, which is necessary to reach the endpoint of the titration.

Answer 2

To determine the number of moles of sodium hydroxide required to react with 1.65 L of 0.500 M sulfuric acid, we can use the balanced equation and stoichiometry. option a

Step-by-step explanation:

To determine the number of moles of sodium hydroxide required to react with 1.65 L of 0.500 M sulfuric acid, we can use the balanced equation for the reaction:

H2SO4 (aq) + 2NaOH(aq) → Na2SO4 (aq) + 2H2O (l)

From the equation, we can see that 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide. Therefore, to calculate the number of moles of sodium hydroxide, we can use the following equation:

moles of NaOH = moles of H2SO4 × 2

moles of NaOH = (0.500 M × 1.650 L) × 2 = 1.65 mol

Therefore, the correct answer is a. 1.65 mol.