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Enter the values for the highlighted varia complete the steps to find the sum: (3x)/(2x-6)+(9)/(6-2x)=(3x)/(2x-6)+(9)/(a(2x-6))

User Tehnix
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To find the sum of the given expression, we need to solve the equation first. Let's go through the steps to find the sum:

Step 1: Rewrite the equation with the highlighted variables:

(3x)/(2x-6) + (9)/(6-2x) = (3x)/(2x-6) + (9)/(a(2x-6))

Step 2: Find a common denominator for the fractions. The common denominator is (2x - 6):

(3x)/(2x-6) + (9)/(6-2x) = (3x)/(2x-6) + (9)/(a(2x-6))

Step 3: Multiply each fraction by the common denominator to eliminate the denominators:

(3x)(a(2x-6))/(2x-6) + (9)(2x-6)/(6-2x) = (3x)(a(2x-6))/(2x-6) + (9)/(a(2x-6))

Step 4: Distribute and simplify:

(6ax^2 - 18ax) + (18x - 54) = (6ax^2 - 18ax) + (9)/(a(2x-6))

Step 5: Combine like terms on both sides of the equation:

6ax^2 - 18ax + 18x - 54 = 6ax^2 - 18ax + (9)/(a(2x-6))

Step 6: Subtract (6ax^2 - 18ax) from both sides:

18x - 54 = (9)/(a(2x-6))

Step 7: Multiply both sides by a(2x-6) to eliminate the denominator on the right side:

(a(2x-6))(18x - 54) = 9

Step 8: Distribute and simplify:

18ax^2 - 54ax - 108ax + 324 = 9

Step 9: Combine like terms:

18ax^2 - 162ax + 324 = 9

Step 10: Subtract 9 from both sides:

18ax^2 - 162ax + 315 = 0

Now, you can use this quadratic equation to solve for the variable "x".

User Thst
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