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Which term of the arithmetic sequence 1, 3, 5, 7, ... is equal to 141

2 Answers

4 votes

Answer:

71

Step-by-step explanation:

2n-1=141

2n=142

n=71

User Nagat
by
7.4k points
2 votes

Final answer:

The 71st term of the arithmetic sequence 1, 3, 5, 7, ... is equal to 141. To find this, the formula for the n-th term of an arithmetic sequence was applied and solved for n.

Step-by-step explanation:

To find which term of the arithmetic sequence 1, 3, 5, 7, ... is equal to 141, we use the formula for the n-th term of an arithmetic sequence: a_n = a_1 + (n - 1)d, where a_n is the n-th term, a_1 is the first term, d is the common difference, and n is the term number.

In this sequence, a_1 = 1 and the common difference d = 2 (since each term increases by 2). Plugging the values into the formula, we are looking for n such that 141 = 1 + (n - 1)×2.

Solving for n, we get:

  • 141 = 1 + 2n - 2
  • 141 = 2n - 1
  • 142 = 2n
  • n = 142 / 2
  • n = 71

Therefore, the 71st term of the sequence is equal to 141.

User Dupersuper
by
7.6k points

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