Question

What volume of a 0.540 M NaOH solution contains 12.5 g of NaOH? 0.169 L 5.92 L 0 0579 1.73 L 0 718L

Answer 1

The volume of a 0.540 M NaOH solution that contains 12.5 g of NaOH is 0.578 L.

Step-by-step explanation:

To find the volume of a 0.540 M NaOH solution that contains 12.5 g of NaOH, you can use the formula:

Molarity (M) = Moles of solute / Volume of solution (L)

First, convert the mass of NaOH to moles using the molar mass of NaOH:

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Moles of NaOH = 12.5 g / 40.00 g/mol = 0.3125 mol

Next, rearrange the formula to solve for the volume of the solution:

Volume of solution (L) = Moles of solute / Molarity

Volume of solution = 0.3125 mol / 0.540 M = 0.578 L

Therefore, the volume of a 0.540 M NaOH solution that contains 12.5 g of NaOH is 0.578 L.

Answer 2

To calculate the volume of a 0.540 M NaOH solution containing 12.5 g of NaOH, you can use the equation Molarity (M) = Moles of solute (mol) / Volume of solution (L). First, convert the grams of NaOH to moles. Then rearrange the molarity equation to solve for the volume of solution. The volume of solution is 0.579 L.

Step-by-step explanation:

To calculate the volume of a 0.540 M NaOH solution containing 12.5 g of NaOH, we need to use the equation:

Molarity (M) = Moles of solute (mol) / Volume of solution (L)

We first need to determine the number of moles of NaOH:

1. 
   
2. 
   

Next, we can rearrange the molarity equation to solve for the volume of solution:

1. 
   
2. 
   
3.