Question

a toy rocket is shot straight up into the air with an initial speed of 45.0 m/s. how long does it take the rocket to reach its highest point? how high does the rocket rise above the ground?

Answer 1

the rocket rises approximately 104.11 meters above the ground.

Step-by-step explanation:

v = u + at

0 = 45.0 m/s + (-9.8 m/s²) * t

t = -45.0 m/s / -9.8 m/s²

t ≈ 4.59 seconds

To find the height the rocket rises above the ground, we can use the kinematic equation:

s = ut + (1/2) * a * t²

h=ut+(1/2) * g *
`t^(2)`

h = 45.0 m/s * 4.59 s + (1/2) * (-9.8 m/s²) * (4.59 s)²

h ≈ 104.11 meters