Question

Balance:

__ V2O5 ----> __V+ __O2

after balancing find:
how many grams of O2 gas can be obtained from the production of 5.50 mol V2O5?

Answer 1

Step-by-step explanation:

2 V2O5 --> 4 V + 5 O2

from the formula, you know that

2 mol V2O5 give 5 mol O2

then 5.50 mol V2O5 will give

(2 mol V2O5)/(5 mol O2)=(5.50 mol V2O5)/(x mol O2)

(x mol O2)=(5.50 mol V2O5)×(5 mol O2)/(2 mol V2O5)

x mol O2 = 13.75

(16×2)g o2 / 1 mol o2 = x g o2 / 13.75 mol o2

32g o2 × 13.75 mol o2 / 1 mol o2 = x g o2 = 440g o2

hope it was helpful!

Answer 2

To find the mass of O2 produced from 5.50 mol V2O5, balance the equation V2O5 --> V2 + (5/2)O2, calculate the moles of O2 produced, and then convert this amount to grams, resulting in 440 grams of O2.

Step-by-step explanation:

Steps to Balance the Reaction and Find the Mass of O2 Produced

To balance the chemical equation V2O5 --> V + O2, we must ensure that the number of atoms for each element is the same on both the reactant and product sides of the equation. The balanced equation is:

• V2O5 --> V2 + (5/2)O2

To calculate the mass of O2 produced from 5.50 mol of V2O5, we use the molar ratio found in the balanced equation. Since each mole of V2O5 produces 2.5 moles of O2, we can calculate the mass of O2 as follows:

1. Calculate the total moles of O2: 5.50 mol V2O5 * (2.5 mol O2 / 1 mol V2O5) = 13.75 mol O2
2. Convert moles of O2 to grams: 13.75 mol O2 * (32.00 g O2/mol) = 440 g O2

Therefore, 440 grams of O2 gas can be obtained from the production of 5.50 mol V2O5.

Remember, the molar mass of O2 (32.00 g/mol) is used here, where 32.00 g/mol represents the sum of the atomic masses of two oxygen atoms.