61.3k views
5 votes
Solve for x. 0 = x^2 + 5x + 8

A.
B.
C.
D.

Solve for x. 0 = x^2 + 5x + 8 A. B. C. D.-example-1
User HPage
by
8.6k points

1 Answer

0 votes

Answer:


\bold{x = (-5 \± i\sqrt7)/(2)}

Explanation:

x^2 + 5x + 8=0

Comparing with ax^2+bx+c=0

we get a = 1, b = 5, and c = 8.

Using the quadratic formula, we have:


x = (-b \± √((b^2- 4ac)))/( 2a)

Substituting these values, we get:


x =( -5 \± √(5^2 - 4*1*8))/(2*1)


x = (-5 \± √(25 - 32))/( 2)


x = (-5 \± √(-7))/( 2)


x = (-5 \± i\sqrt7)/(2)

Therefore, the solutions are:
x = (-5 \± i\sqrt7)/(2)

User Oleksandr Mosur
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories