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Solve for x. 0 = x^2 + 5x + 8

A.
B.
C.
D.

Solve for x. 0 = x^2 + 5x + 8 A. B. C. D.-example-1
User HPage
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1 Answer

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Answer:


\bold{x = (-5 \± i\sqrt7)/(2)}

Explanation:

x^2 + 5x + 8=0

Comparing with ax^2+bx+c=0

we get a = 1, b = 5, and c = 8.

Using the quadratic formula, we have:


x = (-b \± √((b^2- 4ac)))/( 2a)

Substituting these values, we get:


x =( -5 \± √(5^2 - 4*1*8))/(2*1)


x = (-5 \± √(25 - 32))/( 2)


x = (-5 \± √(-7))/( 2)


x = (-5 \± i\sqrt7)/(2)

Therefore, the solutions are:
x = (-5 \± i\sqrt7)/(2)

User Oleksandr Mosur
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