Given balanced equation:
Fe₂O₃ + 2Al → Al₂O₃ + 2Fe
Molar masses:
Fe₂O₃: 159.69 g/mol
Al: 26.98 g/mol
Al₂O₃: 101.96 g/mol
The equation tells us that 1 mole of Fe₂O₃ reacts with 2 moles of Al to produce 1 mole of Al₂O₃.
Step 1: Calculate the number of moles of Al₂O₃ produced:
Using the mole ratio from the balanced equation, we find that the number of moles of Al₂O₃ is equal to the number of moles of Fe₂O₃ used.
So, the moles of Al₂O₃ produced = moles of Fe₂O₃ used = 1 mole.
Step 2: Convert moles to grams:
To convert moles of Al₂O₃ to grams, we multiply by the molar mass of Al₂O₃.
Grams of Al₂O₃ produced = moles of Al₂O₃ produced × molar mass of Al₂O₃
Grams of Al₂O₃ produced = 1 mole × 101.96 g/mol
Grams of Al₂O₃ produced = 101.96 grams
Therefore, 101.96 grams of aluminum oxide (Al₂O₃) are produced in the reaction.