If Nancy pushes an object with twice the force for half the distance, she does the same amount of work.
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.In this scenario, Nancy applies twice the force, which means F is doubled. However, the distance she pushes the object is halved, so d is divided by 2.
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.In this scenario, Nancy applies twice the force, which means F is doubled. However, the distance she pushes the object is halved, so d is divided by 2.Let's assume the original force is F and the original distance is d. Thus, we have:
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.In this scenario, Nancy applies twice the force, which means F is doubled. However, the distance she pushes the object is halved, so d is divided by 2.Let's assume the original force is F and the original distance is d. Thus, we have:Original work, W1 = F * d
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.In this scenario, Nancy applies twice the force, which means F is doubled. However, the distance she pushes the object is halved, so d is divided by 2.Let's assume the original force is F and the original distance is d. Thus, we have:Original work, W1 = F * dIf Nancy pushes the object with twice the force (2F) for half the distance (d/2), the work done, W2, can be calculated as:
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.In this scenario, Nancy applies twice the force, which means F is doubled. However, the distance she pushes the object is halved, so d is divided by 2.Let's assume the original force is F and the original distance is d. Thus, we have:Original work, W1 = F * dIf Nancy pushes the object with twice the force (2F) for half the distance (d/2), the work done, W2, can be calculated as:W2 = (2F) * (d/2) = F * d = W1
If Nancy pushes an object with twice the force for half the distance, she does the same amount of work. Work, in physics, is defined as the product of force and displacement. Mathematically, work (W) is represented as W = F * d, where F is the force applied and d is the displacement.In this scenario, Nancy applies twice the force, which means F is doubled. However, the distance she pushes the object is halved, so d is divided by 2.Let's assume the original force is F and the original distance is d. Thus, we have:Original work, W1 = F * dIf Nancy pushes the object with twice the force (2F) for half the distance (d/2), the work done, W2, can be calculated as:W2 = (2F) * (d/2) = F * d = W1Therefore, Nancy does the same amount of work, regardless of whether she doubles the force and halves the distance or not. The work done is solely determined by the force multiplied by the distance traveled, and in this case, it remains unchanged.