Question

Q.1: Find the value of “p” from the polynomial x2 + 3x + p, if one of the zeroes of the polynomial is 2.

THANKS ​

Answer 1

To find the value of "p" from the polynomial x^2 + 3x + p, if one of the zeroes of the polynomial is 2, we can use the fact that if 2 is a zero of the polynomial, then (x - 2) is a factor of the polynomial.

So, let's divide the polynomial x^2 + 3x + p by (x - 2) using polynomial long division:

___________________

(x - 2) | x^2 + 3x + p

- (x^2 - 2x)

_______________

5x + p

- (5x - 10)

_______________

p + 10

The remainder of the division is p + 10.

Now, since 2 is a zero of the polynomial, the remainder of the division should be zero. Therefore, we can equate the remainder to zero:

p + 10 = 0

Solving for "p", we subtract 10 from both sides:

p = -10

So, the value of "p" is -10.

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