Answer:
(-1, -3) or (3, 13)
Explanation:
Since both equations equal “y”, we can set them equal to each other
4x + 1 = x^2 + 2x - 2
0 = x^2 - 2x - 3
0 = (x + 1)(x - 3)
x = -1 or 3
Now, to find “y”, plug in both values of “x” into any one of the given equations:
y = 4(-1) + 1 = -4 + 1 = -3
y = 4(3) + 1 = 12 + 1 = 13
Thus the answers are x=-1 and y=-3, or x=3 and y=13