79.1k views
5 votes
What is the range of the function f in f(x) = 3x^2 + 18x

User Microcosme
by
8.8k points

1 Answer

2 votes

Answer:

Range of the function f(x) = 3x² +18x is [-27,∞).What is the range of a function?The range of a function is the complete set of all possible resulting values of the dependent variable (y, usually), after we have substituted the domain.Here, we have f(x) = 3x² +18x.Let f(x) = y⇒ y = 3x² +18x⇒ y = 3(x²+6x)⇒ y/3 = x²+6x⇒ y/3 = x²+ 6x + 9 - 9⇒ y/3 = (x+3)² - 9⇒ y/3 + 9 = (x+3)² ⇒ (y+27)/3 = (x+3)² Taking square root on both sides, we get⇒ = x+ 3⇒ = xNow since f(x) = y ⇒ x = f⁻¹(y)⇒ f⁻¹(y) = ⇒ range = [-27,∞).Therefore, range of the function f(x) = 3x² +18x was found to be [-27,∞).

Explanation:

User Anodyne
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories