To find the capacitive reactance (Xc) and current supply (I), we can use the following formulas:
Capacitive reactance (Xc) = 1 / (2πfC)
Current supply (I) = V / Xc
Given:
Frequency (f) = 50 Hz
Capacitance (C) = 5 mF = 5 × 10^(-3) F
Supply voltage (V) = 230 V
First, let's calculate the capacitive reactance:
Xc = 1 / (2π × 50 × 5 × 10^(-3))
Xc = 1 / (0.314 × 10^(-3))
Xc ≈ 318.47 Ω
The capacitive reactance is approximately 318.47 Ω.
Next, let's calculate the current supply:
I = V / Xc
I = 230 / 318.47
I ≈ 0.722 A
The current supply is approximately 0.722 A.
Therefore, the capacitive reactance is approximately 318.47 Ω and the current supply is approximately 0.722 A.