Answer: The heat that is given off is -570J.
Step-by-step explanation:
Step 1: Write the given and the required in the problem.
mass = 50g
specific heat capacity of copper = 0.38J/g°C
Initial Temperature = 80°C
Final Temperature = 50°C
Step 2: This is an example of a Calorimetry problem. The equation to solve this problem is q = msΔT where
q = heat
s = specific heat capacity
ΔT = change in temperature
Step 3: Substitute all the values given and solve for the value of heat.
q = msΔT
q = 50g(0.38J/g°C)(50°C - 80°C)
q = -570J
The heat that is given off is -570J.