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If there are 5 arithmetic means betweeen 5 and b.the last term is 25 then find the value of b​

User Tlaquetzal
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1 Answer

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Answer:

b = 21

Explanation:

If there are 5 arithmetic means between 5 and b and the last term is 25, then we can find the value of b by using the formula for the nth term of an arithmetic sequence:

a_n = a_1 + (n - 1)d

where a_n is the nth term, a_1 is the first term, n is the number of terms, and d is the common difference.

We know that there are 5 arithmetic means between 5 and b. Therefore, there are 7 terms in total (including 5 and b). We also know that the last term is 25. So we have:

a_7 = 25 a_1 = 5 n = 7

We can use these values to solve for d:

a_n = a_1 + (n - 1)d 25 = 5 + (7 - 1)d d = 4

Now that we know d, we can find b by using the formula for the fifth term:

a_5 = a_1 + (5 - 1)d a_5 = 5 + (4)(4) a_5 = 21

Therefore, b = 21.

User Quantik
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