Final answer:
There are 126 rising 4-digit numbers that can be created from decimal digits, calculated using the combinatorial formula C(9, 4), which represents choosing 4 distinct digits from the 9 available.
Step-by-step explanation:
The question asks how many rising 4-digit numbers can be made from the decimal digits. A rising number is defined as a positive integer where every digit is larger than the one to its left. An important thing to note here is that each digit can be used only once because it must be smaller than the one to its right.
Since there are ten digits (0-9) to choose from, and we are looking at 4-digit numbers, the first digit can be any digit from 1 to 9 (0 can't be the first digit as it would not make the number a 4-digit number). The remaining digits must be selected from the remaining pool of digits such that each subsequent digit is larger than the previous one.
To calculate this, we can simply choose 4 distinct digits from the 9 available (since the first digit cannot be 0). The number of ways to choose 4 digits out of 9, without regards to order, is given by the combinatorial formula for combinations (since the order of the digits matters for our problem, they will be arranged in ascending order by default after choosing them). The formula for combinations is expressed as C(n, k) = n! / (k! * (n-k)!), where n is the total number of items to pick from, k is the number of items to pick, and ! denotes factorial.
Therefore, for our case, the combination would be C(9, 4) = 9! / (4! * (9-4)!) = 9! / (4! * 5!) = 126. Thus, there are 126 rising 4-digit numbers that can be made from decimal digits.