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Use the substitution t = -x to solve the given initial-value problem on the interval (-[infinity], 0). 4x²y" + y = 0, y(−1) = 6, y'(−1) = 3

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Final answer:

To solve the given initial-value problem using the substitution t = -x, differentiate twice with respect to t and replace the second derivatives in the original differential equation with the derivative in terms of x. Then, solve for y(x) using standard methods for linear homogeneous differential equations.

Step-by-step explanation:

To solve the given initial-value problem using the substitution t = -x, we first need to differentiate twice with respect to t. Let's start by finding the first derivative, using the chain rule:

dy/dt = dy/dx * dx/dt = dy/dx * (-1)

Next, we differentiate again:

d²y/dt² = d(dy/dt)/dt = d(dy/dx * (-1))/dt = -d²y/dx²

Now, replace the second derivative in the original differential equation with the derivative in terms of x:

4x²(-d²y/dx²) + y = 0

4x²d²y/dx² + y = 0

This is a linear homogeneous differential equation. Solve for y(x) using standard methods for this type of equation.

User Paul Podgorsek
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