The balanced equation for the reaction between KMnO4 and KNO4 can be written as shown below:3KMnO4 + 2KNO4 + H2O → 5KNO3 + 3MnO2 + 4O2To determine the moles of KMnO4 required, we need to first find the number of moles of KNO4 involved in the reaction.
The molar mass of KNO4 is given as:KNO4 = 39.1 + 14.0 + 64.0 = 117.1 g/molTherefore, the number of moles of KNO4 in 11.4 g of KNO4 is:No. of moles = mass/molar mass = 11.4/117.1 = 0.0973 molAccording to the equation, 3 moles of KMnO4 react with 2 moles of KNO4.
Therefore, the number of moles of KMnO4 required is given by:No. of moles of KMnO4 = (3/2) x 0.0973 = 0.146 molTo find the mass of KMnO4 required, we use its molar mass:Molar mass of KMnO4 = 39.1 + 54.9 + 64.0 + (4 x 16.0) = 158.0 g/molTherefore, the mass of KMnO4 required is:Mass = no. of moles x molar mass = 0.146 x 158.0 = 23.1 gHence, a detailed explanation of how to calculate the moles and grams of KMnO4 needed to carry out the reaction on 11.4 grams of KNO4 has been provided.