I am assuming the left side of every equation is equal to
Answer:
1. 3
2. 3, 3
3. 1200, 15
4. 1305
Explanation:
1)
We know each side needs to be equal to each other. For the first equation, we should set the box equal to x
Then, we should simplify inside the parenthesis.
As we can see, we have a common value of 435 on both sides. We can cancel that out on both sides to get our answer.
2)
In this equation, we can see that the 3 is multiplied into the same parenthesis we were just looking at in the first equation. This causes the 3 to be distributed across the 400, 30, and the 5. Now, we just fill in the blanks. We notice that the 30 is missing, which would be multiplied by a 3. And we can see the 5 is being multiplied by an unknown number, which would need to be 3 to keep the distribution on the right side of the equation consistent.
3)
We now have the information that 30*3 = 90, as the tens place is holding the same 30 * 3 and 90. This means that we multiplied the numbers by 3 individually using our method of distribution. Essentially, we are simplifying the previous equation.
From here on out, we can just multiply the values by 3, which gives us our two answers.
4)
Simply enough,
However, we do also have context clues. We just multiplied numbers together in the previous equations. We are left with
from equation 3. Simplifying this equation will leave us with a sum of 1305, which is the answer to this equation.
I recommend taking the time to learn this process. This specific equation is teaching you ways to easily break down scary looking multiplication problems. It is much easier to multiply 400 by 3 and 30 by 3 and 5 by 3 and then add them together than to just try and bruteforce 435*3. This is a very effective example of how people break down gradually more difficult problems. This will provide excellent groundwork for the future when you move from Algebra 1 to Geometry, Precalculus, and Calculus.