Final answer:
To find the volume of the solid obtained by rotating the region bounded by the given curves about specified lines, we use the method of cylindrical shells. The formula for the volume of the solid obtained by rotating the region about the y-axis is V = ∫πr(x)h(x)dx, where r(x) is the distance from the axis of rotation to the function and h(x) is the height of each shell. For the given curves y = ln x, y = 0, and x = 2, the integral would be V = ∫πx(ln x)dx. Similarly, for the given curves y = sin^-1 x, y = π/2, and x = 0, and the line y = 3, the integral would be V = ∫π(3 - y)(x)dy.
Step-by-step explanation:
To set up the integral for the volume of the solid obtained by rotating the region bounded by the curves y = ln x, y = 0, and x = 2 about the y-axis, we will use the method of cylindrical shells. The formula for the volume of a solid obtained by rotating the region bounded by the curves about the y-axis is:
V = ∫πr(x)h(x)dx
where r(x) is the distance from the axis of rotation to the function, and h(x) is the height of each shell. In this case, r(x) = x and h(x) = y. Plugging these values into the formula, we get:
V = ∫πx(ln x)dx
To set up the integral for the volume of the solid obtained by rotating the region bounded by the curves y = sin^-1 x, y = π/2, and x = 0 about the line y = 3, we will also use the method of cylindrical shells. The formula for the volume of a solid obtained by rotating the region bounded by the curves about a vertical line is:
V = ∫πr(y)h(y)dy
where r(y) is the distance from the axis of rotation to the function, and h(y) is the height of each shell. In this case, r(y) = 3 - y and h(y) = x. Plugging these values into the formula, we get:
V = ∫π(3 - y)(x)dy