Question

Identify the focus of the parabola. x+4 = 1/8 (y-3)^2

Answer 1

(-2,3)

Explanation:

Rewrite in the form of
`(y-k)^2=4a(x-h)`:

`x+4=(1)/(8)(y-3)^2\\8(x+4)=(y-3)^2\\(y-3)^2=4(2)(x+4)`

Therefore,
`a=2`, so the focus of the parabola is
`(a+h,k)=(2+(-4),3)=(-2,3)`