Question

A line passes through y=-3 and had a gradient of 3/5. Find the equation of the line

Answer 1

y=3/5x-3

Explanation:

Write the equation of the line with the given information. There are two equations we can utilize for lines and are given as follows.

`\boxed{\left\begin{array}{ccc}\text{\underline{Point-Slope Form:}}\\y-y_1=m(x-x_1)\\\\\text{Where...}\\\bullet \ m \ \text{is the slope of the line} \\ \bullet \ (x_1,y_1) \ \text{is a point on the line} \end{array}\right} \ \text{or} \ \boxed{\left\begin{array}{ccc}\text{\underline{Slope-Intercept Form:}}\\y=mx+b\\\\\text{Where...}\\\bullet \ m \ \text{is the slope of the line} \\ \bullet \ b \ \text{is the y-intercept of the line} \end{array}\right}`

We are given the gradient, which is also referred to as the slope or rate of change. We are also given the line's y-intercept. Thus, we will use the slope-intercept form of a line.

Given:

m=3/5

b=-3

Plugging these values into the equation we get a final answer of...

y=3/5x-3