To calculate the molarity of vinegar, we need to know the moles of acetic acid (the main component of vinegar) and the volume of vinegar used.
The change in volume during the titration is:
Change in volume = Final volume - Initial volume
= 33.5 mL - 12.3 mL
= 21.2 mL
Assuming that the density of vinegar is approximately 1 g/mL, we can convert the change in volume to grams:
Change in volume (mL) × Density (g/mL) = Mass (g)
21.2 mL × 1 g/mL = 21.2 g
Next, we need to convert the mass of acetic acid to moles. The molar mass of acetic acid (CH3COOH) is approximately 60.05 g/mol:
Moles = Mass (g) / Molar mass (g/mol)
= 21.2 g / 60.05 g/mol
≈ 0.353 mol
Finally, we calculate the molarity of vinegar using the moles and total volume:
Molarity = Moles / Total volume (L)
= 0.353 mol / 0.0212 L
≈ 16.65 M
Therefore, based on the information provided, the molarity of vinegar is approximately 16.65 M.