Question

PLEEEEEASE HELP!!

A Ferris wheel has a radius of 75 feet. two particular cars are located such that the central angle between them is 145°. To the nearest tenth, what is the length of the intercepted arc between those two cars on the Ferris wheel? (3 points)

Answer 1

To calculate the length of the intercepted arc between the two cars on the Ferris wheel, we need to use the formula:

Arc Length = θ/360° * 2πr

where θ is the central angle in degrees, r is the radius of the Ferris wheel, and π is a mathematical constant approximately equal to 3.14159.

In this case, the central angle between the two cars is 145°, and the radius of the Ferris wheel is 75 feet. Plugging these values into the formula, we get:

Arc Length = 145/360° * 2π * 75

Arc Length ≈ 0.4028 * 2π * 75

Arc Length ≈ 0.4028 * 150π

Arc Length ≈ 60.42π

To find the length of the intercepted arc to the nearest tenth, we can approximate π as 3.14:

Arc Length ≈ 60.42 * 3.14

Arc Length ≈ 189.77 feet

Therefore, to the nearest tenth, the length of the intercepted arc between the two cars on the Ferris wheel is approximately 189.8 feet.

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