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HURRY PLEASE

Q.14

If
y=3x^(2) -9

A.
y^(-1) = -\sqrt(x+9)/(3) such that x is greater than or equal to negative nine

B.
y^(-1) =-\sqrt(x+9)/(3) such that x id less than or equal to negative nine

C.
y^(-1) = -\sqrt (x)/(3) +9 such that x is less than or equal to zero

D.
y^(-1) = -\sqrt (x)/(3) + 9 such that x is greater than or equal to zero

2 Answers

7 votes

Answer:

the answer is A

Explanation:

Adding on to Voidspace101's answer,

For inverse, we'll get,


x=3y^2-9\\x+9=3y^2\\(x+9)/3=y^2\\y=√((x+9)/3) \\and\\y=\ -sqrt{(x+9)/3} \\

now, to get a positive number inside the square root,

we have the condition,

x + 9 is greater than or equal to 0

so,

x+9 > 0

x>-9

so x has to be equal to or greater than -9

hence the correct answer is A

User Khaur
by
7.5k points
7 votes

Answer: B

Explanation:

This is inverse.

Essentially, you switch y for x.

So;


x=3y^2-9


x+9=3y^2


(x+9)/3=y^2


y=√((x+9)/3)

User Wally Hartshorn
by
7.5k points

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