Answer:
a.
1. The maximum signal that a cell could send for Signal molecule A is (1000 molecules/cell/second) * (3600 seconds/hour) * (100,000 daltons/molecule) * (1.66E-24 g/dalton) = 6.0E-19 g/cell/hr.
2. The maximum signal that a cell could send for Signal molecule B is (5000 molecules/cell/second) * (3600 seconds/hour) * (50,000 daltons/molecule) * (1.66E-24 g/dalton) = 2.4E-18 g/cell/hr.
b. Signal molecule B is secreted at a higher rate by a factor of 4.
c. If equivalent fluxes of both molecules were necessary signals for a cellular-fate process, Signal molecule A would be the limiting molecule since it has a lower maximum signal per cell per hour.