Question

Work of 3 Joules is done in stretching a spring from its natural length to 11 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (11 cm)? Don't forget to enter the correct units.

Answer 1

I got 0.273N

Step-by-step explanation:

The hint here is "Work of 3J". So, we know that the formula we're going to be using is;

W = F × d

With the given distance of 11cm, we now just have to substitute the values to find the force;

3 = F × 11

3/11 = F

∴ F = 0.273N

I hope this helps! Let me know if I have any misconceptions or miscalculations! :)