Question

At a certain university there are 10 different time periods during which classes can be scheduled. If there are 390 different classes, what is the minimum number of different rooms that will be needed

Answer 1

The minimum number of different rooms for accommodating 390 classes if there are 10 different time periods is 39

Explanation:

Number of time periods = 10

Number of Classes = 390

Now, if we have a single room, then we can accommodate 10 classes

if we have 2 rooms, we can accommodate (10)(2) = 20 classes

and so on

so we have the relation,

(number of rooms)(number of time periods) = (number of classes that can be accommodated)

We need to find the number of rooms for 390 classes, given that number of time periods is 10, so we get,

(number of rooms)(10) = 390

number of rooms = 390/10

number of rooms =39