Question

TIME REMAINING 59:53 Mr. Franklin uses a machine that has an efficiency of 80%. The machine applies a force of 800 N through a distance of 20 m. Mr. Franklin applies a force of 50 N on the machine. Through what distance does Mr. Franklin apply the force

Answer 1

I got 256m

Step-by-step explanation:

I'm not quite sure if my answer is right so, don't fully rely on mine.

First, you would need to calculate the work done by the machine with the formula;

W = F × d

W = 800 × 20

W = 16000J

This is the total energy used by the machine. I substituted this energy into this formula;

input energy/total energy × 100 = efficiency

"x" will represent the input energy.

So;

x/16000 × 100 = 80%

The answer should be around 12800J.

Then, using the work done formula again, substitute the energy into the equation like so;

12800 = 50 × d

d = 12800/50

∴ d = 256m

I hope this gives you an idea on how to solve it. Please let me know if I have any miscalculations and misconceptions! :)