Question

Your car produces about 30 kW of power to maintain a constant speed of 31 m/s on the highway. What average force does the engine exert

Answer 1

The average force exerted by the engine to maintain a speed of 31 m/s, given a power output of 30 kW, is approximately 967.74 newtons.

Step-by-step explanation:

To calculate the average force that the car engine exerts to maintain a constant speed of 31 m/s, we use the formula for power (P = F * v), where P is the power, F is the force, and v is the velocity. Given that the car produces about 30 kW of power to maintain this speed, the formula can be rearranged to find the force (F = P / v).

Using the given values:
P = 30 kW = 30,000 W (since 1kW = 1000 W)
v = 31 m/s
Therefore, F = 30,000 W / 31 m/s ≈ 967.74 N.

The average force exerted by the engine to maintain a constant speed of 31 m/s is approximately 967.74 newtons.

Answer 2

The average force exerted by the engine to maintain a constant speed of 31 m/s on the highway, given a power output of 30 kW, is approximately 967.74 newtons.

Step-by-step explanation:

To find the average force that the engine exerts to maintain a constant speed, we use the formula for power, which relates force, velocity, and power:

Power = Force × Velocity

Given that the power is 30 kW (or 30,000 W) and the velocity is 31 m/s, we can rearrange the formula to solve for force:

Force = Power / Velocity

Force = 30,000 W / 31 m/s

Force = 967.74 N (approximately)

The engine therefore exerts an average force of approximately 967.74 newtons to maintain the constant speed of 31 m/s on the highway.