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Find the radius of the path described by a proton moving at 175 km/s in a plane perpendicular to a 64.6- mT magnetic field.

User Suanne
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The radius of the path of a charged particle moving in a magnetic field is given by the formula:

r = mv/(qB),

where:
- r is the radius,
- m is the mass of the proton (≈ 1.67 x 10^-27 kg),
- v is the velocity of the proton (175 km/s = 175000 m/s),
- q is the charge of the proton (≈ 1.60 x 10^-19 C), and
- B is the magnetic field strength (64.6 mT = 64.6 x 10^-3 T).

Substituting the given values into the formula:

r = (1.67 x 10^-27 kg * 175000 m/s) / (1.60 x 10^-19 C * 64.6 x 10^-3 T)

This gives a radius r of approximately 0.302 meters or 30.2 cm.
User Le Duy Khanh
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