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What is the area of a square that has a side length of -3xy^3 feet?

User Ajmurmann
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Answer:

9x^2y^6 square feet.

Explanation:

The area of a square is the length of one of its sides multiplied by itself.

If the side length of a square is -3xy^3 feet,

then the area of the square is

-3xy^3 * -3xy^3 = 9x^2y^6

Therefore, the area of the square is 9x^2y^6 square feet.

User Andrew Allen West
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